One Way Anova Example Problems With Solutions. To see if there is a statistically significant difference in mean exam scores. H 0 null hypothesis.
Ssgroup 1511 45 3 1 3022 9. A tukey post hoc test revealed significant pairwise differences between fertilizer types 3 and 2 with an average difference of 0 42 bushels acre p 0 05 and between fertilizer types 3 and 1 with an average difference of 0 59 bushels acre p 0 01. Sstr n 1 y 1 y 2 n 2 y 2 y 2 n 3 y 3 y 2 n 4 y 4 y 2 4 628 0 494 1 2 5 478 8 494 1 2 5 518 8 494 1 2 6 397 0 494 1 2 132 508 2 sse n 1 1 s 1 2 n 2 1 s 2 2 n 3 1 s 3 2 n 4 1 s 4 2.
μ 1 μ 2 μ 3 μ k all the population means are equal h 1 null hypothesis.
μ 1 μ 2 μ 3 μ k all the population means are equal h 1 null hypothesis. Construct the one way anova table for the data. Ssgroup 1511 45 3 1 3022 9. One way analysis of variance prediction using multiple linear regression active ˆˆ10 125 101 µ ˆ β 12 35 2 225 10 125 passive 11 375 ˆˆ 202 µ ˆ β 12 35 0 97 11 38 no exercise 11 71 ˆˆ 303 µ ˆ β 12 35 0 64 11 71 control 12 35 40 µ ˆ ˆ β12 35.
